Integrand size = 13, antiderivative size = 67 \[ \int \log ^2\left (\frac {c (b+a x)}{x}\right ) \, dx=\frac {(b+a x) \log ^2\left (a c+\frac {b c}{x}\right )}{a}-\frac {2 b \log \left (c \left (a+\frac {b}{x}\right )\right ) \log \left (-\frac {b}{a x}\right )}{a}-\frac {2 b \operatorname {PolyLog}\left (2,1+\frac {b}{a x}\right )}{a} \]
[Out]
Time = 0.05 (sec) , antiderivative size = 67, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.385, Rules used = {2503, 2499, 2504, 2441, 2352} \[ \int \log ^2\left (\frac {c (b+a x)}{x}\right ) \, dx=\frac {(a x+b) \log ^2\left (a c+\frac {b c}{x}\right )}{a}-\frac {2 b \log \left (-\frac {b}{a x}\right ) \log \left (c \left (a+\frac {b}{x}\right )\right )}{a}-\frac {2 b \operatorname {PolyLog}\left (2,\frac {b}{a x}+1\right )}{a} \]
[In]
[Out]
Rule 2352
Rule 2441
Rule 2499
Rule 2503
Rule 2504
Rubi steps \begin{align*} \text {integral}& = \int \log ^2\left (a c+\frac {b c}{x}\right ) \, dx \\ & = \frac {(b+a x) \log ^2\left (a c+\frac {b c}{x}\right )}{a}+\frac {(2 b) \int \frac {\log \left (a c+\frac {b c}{x}\right )}{x} \, dx}{a} \\ & = \frac {(b+a x) \log ^2\left (a c+\frac {b c}{x}\right )}{a}-\frac {(2 b) \text {Subst}\left (\int \frac {\log (a c+b c x)}{x} \, dx,x,\frac {1}{x}\right )}{a} \\ & = \frac {(b+a x) \log ^2\left (a c+\frac {b c}{x}\right )}{a}-\frac {2 b \log \left (c \left (a+\frac {b}{x}\right )\right ) \log \left (-\frac {b}{a x}\right )}{a}+\frac {\left (2 b^2 c\right ) \text {Subst}\left (\int \frac {\log \left (-\frac {b x}{a}\right )}{a c+b c x} \, dx,x,\frac {1}{x}\right )}{a} \\ & = \frac {(b+a x) \log ^2\left (a c+\frac {b c}{x}\right )}{a}-\frac {2 b \log \left (c \left (a+\frac {b}{x}\right )\right ) \log \left (-\frac {b}{a x}\right )}{a}-\frac {2 b \text {Li}_2\left (1+\frac {b}{a x}\right )}{a} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.94 \[ \int \log ^2\left (\frac {c (b+a x)}{x}\right ) \, dx=\frac {\log \left (\frac {c (b+a x)}{x}\right ) \left (-2 b \log \left (-\frac {b}{a x}\right )+(b+a x) \log \left (\frac {c (b+a x)}{x}\right )\right )-2 b \operatorname {PolyLog}\left (2,1+\frac {b}{a x}\right )}{a} \]
[In]
[Out]
\[\int \ln \left (\frac {c \left (a x +b \right )}{x}\right )^{2}d x\]
[In]
[Out]
\[ \int \log ^2\left (\frac {c (b+a x)}{x}\right ) \, dx=\int { \log \left (\frac {{\left (a x + b\right )} c}{x}\right )^{2} \,d x } \]
[In]
[Out]
\[ \int \log ^2\left (\frac {c (b+a x)}{x}\right ) \, dx=2 b \int \frac {\log {\left (a c + \frac {b c}{x} \right )}}{a x + b}\, dx + x \log {\left (\frac {c \left (a x + b\right )}{x} \right )}^{2} \]
[In]
[Out]
none
Time = 0.22 (sec) , antiderivative size = 113, normalized size of antiderivative = 1.69 \[ \int \log ^2\left (\frac {c (b+a x)}{x}\right ) \, dx=x \log \left (\frac {{\left (a x + b\right )} c}{x}\right )^{2} + \frac {2 \, b \log \left (a x + b\right ) \log \left (\frac {{\left (a x + b\right )} c}{x}\right )}{a} + \frac {{\left (\frac {c \log \left (a x + b\right )^{2}}{a} - \frac {2 \, {\left (\log \left (\frac {a x}{b} + 1\right ) \log \left (x\right ) + {\rm Li}_2\left (-\frac {a x}{b}\right )\right )} c}{a}\right )} b - \frac {2 \, {\left (c \log \left (a x + b\right ) - c \log \left (x\right )\right )} b \log \left (a x + b\right )}{a}}{c} \]
[In]
[Out]
\[ \int \log ^2\left (\frac {c (b+a x)}{x}\right ) \, dx=\int { \log \left (\frac {{\left (a x + b\right )} c}{x}\right )^{2} \,d x } \]
[In]
[Out]
Timed out. \[ \int \log ^2\left (\frac {c (b+a x)}{x}\right ) \, dx=\int {\ln \left (\frac {c\,\left (b+a\,x\right )}{x}\right )}^2 \,d x \]
[In]
[Out]